This has probably already been discussed at some point but I'd appreciate it if someone could either explain this to me in simple terms or point me towards an easily-understood explanation. I don't have an engineering background nor am I good at math.
According to Hegel, my H390's "power is delivered through a low 0.014-0.048ohm source impedance". I've read elsewhere that the amp's input impedance should be at least 10X the DAC's output impedance and preferably more. Does Hegel's description of the H390's input impedance as "low" suggest it will be difficult to find DAC that will be well matched?
Specific Example:
I'm researching DACs and the Ferrum Wandla GoldenSound Edition looks interesting. It's output impedance is reputedly 22 ohms unbalanced. It also has "a hardware voltage divider circuit that allows the user to adjust the output voltage from just under 10 Vrms to just under 4 Vrms. This adjustment allows the WANDLA to be compatible with a wider range of amplifiers".
Would the Wandla GoldenSound Edition be a good match for the H390?
According to Hegel, my H390's "power is delivered through a low 0.014-0.048ohm source impedance". I've read elsewhere that the amp's input impedance should be at least 10X the DAC's output impedance and preferably more. Does Hegel's description of the H390's input impedance as "low" suggest it will be difficult to find DAC that will be well matched?
Specific Example:
I'm researching DACs and the Ferrum Wandla GoldenSound Edition looks interesting. It's output impedance is reputedly 22 ohms unbalanced. It also has "a hardware voltage divider circuit that allows the user to adjust the output voltage from just under 10 Vrms to just under 4 Vrms. This adjustment allows the WANDLA to be compatible with a wider range of amplifiers".
Would the Wandla GoldenSound Edition be a good match for the H390?