You are better than me in optical curve matchingThe missing piece of the puzzle is what the speaker's frequency response curve is like up there. Take a look at the second graph in this link, which shows the effects of the brilliance control:http://www.stereophile.com/content/sound-lab-1-electrostatic-loudspeaker-measurements
With the brilliance control max'd out we get the impedance curve that you posted, along with a 10 dB peak centered on about 17 kHz (when driven by a voltage paradigm amp)!
In this case, power paradigm amp + very low impedance in the high treble + 10 dB peak in the high treble = beautiful high treble!!
You see, the speaker's impedance curve zigs where the frequency response curve zags, and that's a recipe for potentially wonderful synergy with a power paradigm amp.
![i-6zHw659.png](http://amirviews.smugmug.com/photos/i-6zHw659/0/O/i-6zHw659.png)
I don't see the inversion you speak off. The two massive peaks in impedance < 1 Khz don't have corresponding dips in response. As a result, if I am following your arguments, they would cause sharp increases in frequency response in those regions, adding significant low-mid frequency colorations to a speaker that was already bass heavy.
I don't see how any speaker with such wild variations in impedance would have been designed with "constant power" amps in mind. Or any tube design with that super low high frequency characteristics. In that regard, I think the recommendation you heard from SoundLab folks was not based on any of this. But rather, as I pointed out to Ralph, was a preference the listener had developed for the heavily modified frequency response and not any sense of accuracy.
Well, that constant current times the output impedance equals dissipated power in the output stage of his amp. Ralph, can your amp sustain short circuit this way? The reviewer's tube amp blew up even when just driving 1-4 watts.Isn't that virtual dead short at 20 kHz going to damage Ralph's amp? Nope, not even with a 20 kHz sine wave! Instead of frying its output stage trying to dump nearly infinite wattage into a dead short, like a "constant voltage" amp would, Ralph's amp delivers essentially no wattage into a dead short and so nothing overheats. In other words, into a very low impedance load, it starts to behave like a "constant current" amp.